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6a^2+22a-8=0
a = 6; b = 22; c = -8;
Δ = b2-4ac
Δ = 222-4·6·(-8)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-26}{2*6}=\frac{-48}{12} =-4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+26}{2*6}=\frac{4}{12} =1/3 $
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